{"id":555,"date":"2019-08-12T15:55:12","date_gmt":"2019-08-12T10:25:12","guid":{"rendered":"https:\/\/www.physicsacademyonline.com\/blog\/?p=555"},"modified":"2021-02-25T14:02:03","modified_gmt":"2021-02-25T08:32:03","slug":"solve-jee-main-2017-with-a-smile-iii","status":"publish","type":"post","link":"https:\/\/www.physicsacademyonline.com\/blog\/jee-main\/solve-jee-main-2017-with-a-smile-iii.html","title":{"rendered":"SOLVE JEE (MAIN) 2017 WITH A SMILE \u2013 III"},"content":{"rendered":"<h3 style=\"font-size: 1.20em; font-weight: normal !important;\"><i>Let <em><del>Us<\/del> <\/em><\/i><span style=\"font-family: impact; letter-spacing: 1.5px; font-size: 24px; color: #000;\">YOU<\/span><i> Solve Physics JEE (MAIN) 2017 Physics Paper<\/i><\/h3>\n<p>We encourage students to attempt more Physics MCQs from JEE (Main) 2017, Paper-1. As usual, our job is limited to linking a question to relevant theory(ies), and no further. You can study the theories from a large pool of articulate, lively video lectures @ <a href=\"https:\/\/www.physicsacademyonline.com\" target=\"_blank\" rel=\"noopener\">PhysicsAcademyOnline.com.<\/a>. As you solve the questions <em>on your own<\/em>, expertise and confidence build up bit by bit in you, making you ready for the Engineering and Medical Entrance Examinations. A video solution at the end of every question lets you know, eventually, if you got the correct answer.<\/p>\n<p><strong><u>Question 07<\/u>:<\/strong>\u00a0\u00a0 The variation of acceleration due to gravity, g, with distance, d, from the centre of the earth is best represented by (R is earth&#8217;s radius):<\/p>\n<p><a href=\"https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img.png\"><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-large wp-image-693\" src=\"https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img-1024x221.png\" alt=\"\" width=\"740\" height=\"160\" srcset=\"https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img-1024x221.png 1024w, https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img-300x65.png 300w, https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img-768x166.png 768w, https:\/\/www.physicsacademyonline.com\/blog\/wp-content\/uploads\/2019\/08\/Blog16_Img.png 1081w\" sizes=\"(max-width: 740px) 100vw, 740px\" \/><\/a><\/p>\n<p>The shape of the g vs d graph depends on how the acceleration due to gravity, g, varies below and above earth&#8217;s surface. How does g vary with depth below the ground? Subscribe to <a href=\"https:\/\/www.physicsacademyonline.com\" target=\"_blank\" rel=\"noopener\">www.PhysicsAcademyOnline.com<\/a>, and find the relevant formula here: <span style=\"color: #8270a4;\">\u00a0<\/span><em><span style=\"color: #8270a4;\"> Chapter Name \u2013 Mechanics; Category \u2013\u00a0 Basic; Topic Name \u2013 Gravitation; Video Name \u2013 Variation of Acceleration Due to Gravity I.<\/span><\/em><\/p>\n<p>The shape of the left part of the graph for d \u2264 R can be predicted. How does g vary with altitude above the ground? The relevant formula is derived in the same lecture mentioned above .<\/p>\n<p>The shape of the right part of the graph for d \u2265 R can be predicted. Are you still waiting to pick your choice?<\/p>\n<p>I know it, I know it. Smart students have stopped following me after the first step! Because they noticed only one option gives the correct shape of graph for d \u2264 R. So why should they waste more time with this question? MCQs sometimes offer such pleasant shortcut.<\/p>\n<p>As a matter of fact, our lectures @ <a href=\"https:\/\/www.physicsacademyonline.com\" target=\"_blank\" rel=\"noopener\">PhysicsAcademyOnline.com.<\/a> are so exhaustive, you will find the same graph within the above lecture .<\/p>\n<p>&nbsp;<\/p>\n<p><iframe loading=\"lazy\" width=\"740\" height=\"416\" src=\"https:\/\/www.youtube.com\/embed\/e6INzwi-6o8?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe><\/p>\n<p>&nbsp;<\/p>\n<p><strong><u>Question 08<\/u>:<\/strong>\u00a0 A copper ball of mass 100 g is at a temperature T. It is dropped in a copper calorimeter of mass 100 g, filled with 170 g of water at room temperature 30\u00b0C. Subsequently, the temperature of the system is found to be 75\u00b0C. Specific heat of copper is 0.1 cal\/g-\u00b0C. T is:<\/p>\n<p>(1) 800\u00b0C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (2) 885\u00b0C \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (3) 1250\u00b0C\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0 (4) 825\u00b0C<\/p>\n<p>After the ball is dropped, on what principle does heat exchange take place between different agents? Study from the lecture: <em><span style=\"color: #8270a4;\"> Chapter Name \u2013 Heat and Thermodynamics; Category \u2013\u00a0 Basic; Topic Name \u2013 Calorimetry and Phase Change; Video Name \u2013 Principle of Calorimetry, and Determination of Specific Heat by Method of Mixtures.<\/span><\/em><\/p>\n<p>How much heat is lost, and by which agent(s)? How much heat is gained, and by which agent(s)? Although the above lecture discusses a similar situation, to learn from the basics follow: <span style=\"color: #8270a4;\">\u00a0 <em>Chapter Name \u2013 Heat and Thermodynamics; Category \u2013\u00a0 Basic; Topic Name \u2013 Calorimetry and Phase Change; Video Name \u2013 Definition of Heat and Types of Heat Capacity.<\/em><\/span><\/p>\n<p>A simple calculation gives T.<\/p>\n<p><iframe loading=\"lazy\" width=\"740\" height=\"416\" src=\"https:\/\/www.youtube.com\/embed\/jH165V5tsDg?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Let Us YOU Solve Physics JEE (MAIN) 2017 Physics Paper We encourage students to attempt more Physics MCQs from JEE (Main) 2017, Paper-1. As usual, our job is limited to&#8230;<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[13,26],"tags":[],"_links":{"self":[{"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/posts\/555"}],"collection":[{"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/comments?post=555"}],"version-history":[{"count":9,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/posts\/555\/revisions"}],"predecessor-version":[{"id":695,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/posts\/555\/revisions\/695"}],"wp:attachment":[{"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/media?parent=555"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/categories?post=555"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.physicsacademyonline.com\/blog\/wp-json\/wp\/v2\/tags?post=555"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}