{"id":561,"date":"2019-08-12T16:30:30","date_gmt":"2019-08-12T11:00:30","guid":{"rendered":"https:\/\/www.physicsacademyonline.com\/blog\/?p=561"},"modified":"2021-02-25T14:01:50","modified_gmt":"2021-02-25T08:31:50","slug":"solve-jee-main-2017-with-a-smile-iv","status":"publish","type":"post","link":"https:\/\/www.physicsacademyonline.com\/blog\/jee-main\/solve-jee-main-2017-with-a-smile-iv.html","title":{"rendered":"SOLVE JEE (MAIN) 2017 WITH A SMILE \u2013 IV"},"content":{"rendered":"

Let Us<\/del> <\/em><\/i>YOU<\/span> Solve Physics JEE (MAIN) 2017 Physics Paper<\/i><\/h3>\n

We shall guide you to solve few more Physics questions from JEE (Main) 2017, Paper-1. All students at + 2 level, who wish to pursue B.E. \/B. Tech courses in Indian Engineering Institutes, must secure good ranks in JEE (Main). So it’s a good idea you learnt to connect the questions to the relevant theories, study them with absolute clarity<\/em> from the video lectures\u00a0 @ PhysicsAcademyOnline.com<\/a>, and apply them to solve the questions. This way, if a close contact is purposefully maintained between questions and theories, the study of Physics becomes enjoyable and stress-free. Needless to say, more practice leads you to more lectures at both basic and advanced levels. In turn they make you more self-reliant and fighting fit for the Competitive Exams ahead. And you can always check your own solution against our video solution given at the end of every question.<\/p>\n

Question 09<\/u>:<\/strong>\u00a0 An external pressure P is applied to a cube at 0\u00b0C, so that it is equally compressed from all sides. K is the bulk modulus of the material of the cube and \u00a0\u03b1<\/em>\u00a0 is its coefficient of linear expansion. Suppose we want to bring the cube to its original size by heating. The temperature should be raised by:<\/p>\n

(1) P\/3\u03b1<\/em>K\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 \u00a0 \u00a0 (2) P\/\u03b1<\/em>K\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (3) 3\u03b1<\/em> \/PK\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0 (4) 3PK\u03b1<\/em><\/p>\n

Of the various options, which has\/have the same dimension as temperature? subscribe to PhysicsAcademyOnline.com<\/a>, and learn the technique here:\u00a0 Chapter Name \u2013 Mechanics; Category \u2013\u00a0 Basic; Topic Name \u2013 Physical Quantities and Their Measurement; Video Name \u2013 Uses of Dimensional Analysis.<\/span><\/em><\/p>\n

Still, you have to choose between two options. What is the relation between the coefficients of volume and linear expansion? Discussed here:\u00a0 Chapter Name \u2013 Heat and Thermodynamics; Category \u2013\u00a0 Basic; Topic Name \u2013 Thermal Expansion; Video Name \u2013 Thermal Expansion of Solids.<\/span><\/em><\/p>\n

Now, you can easily guess the correct option. That was a shortcut. Another method is discussed below.<\/p>\n

What is the change in volume of the cube under pressure? Formula here:\u00a0 Chapter Name \u2013 Elasticity and Fluid Mechanics; Category \u2013\u00a0 Basic; Topic Name \u2013 Elasticity; Video Name \u2013 Bulk Modulus & Relations among Elastic Constants.<\/span><\/em><\/p>\n

What is the required change in volume of the cube by heating? How do you express it in terms of coefficient of linear expansion, a<\/em> , and temperature rise? Discussed in the same lecture titled “Thermal Expansion of Solids”.<\/p>\n

You are close to the answer.<\/p>\n